Which constructor will fire first




















The call can be prefixed with the inherited keyword in order to call the base class. They may also not be preceded by any try Block or exit Statements. Each constructor may also perform no more than one call to a different constructor.

Also note that access to self is not allowed in a constructor until after the deferred constructor call. This includes:. Some special considerations apply to constructors in Mapped Types. Please refer to the Constructors sub-topic there for details. Types can contain Fields and Stored Properties defined with an initializer that sets a start value for them. Initialization of these fields happens as part of the constructors, with code automatically generated by the compiler.

There are certain rules that are relevant for understanding how fields will be initialized. Note that this only applies to explicit initializers. All fields or properties will of course be pre-set to their default value e. Also note that this does not apply to Properties marked with the lazy Member Modifier , which defers execution of the initializer until the first time the property is accessed. If a class declares no constructors of its own, it automatically inherits all public constructors of the base class.

If the base class was abstract , any protected constructors are also inherited, and made public by default. Then the non-static variables of the base class are initialized.

We specifically assigned them initial values, which are then replaced in the constructor. The Animal constructor has not finished yet, but the initial values of brain and heart have already been assigned:.

The base class constructor starts. We've already convinced ourselves that this step is fourth: in the first three steps at the beginning of the Animal constructor, many variables have already been assigned values. Non-static fields of the child class Cat are initialized. So it appears as if the base constructor is being called first. What if the base constructor has arguments, then would it still be automatically called? David Pokluda David Pokluda Don't remember it, understand it.

Nice work. So: the derived is executed first, but it "looks like" the base was executed first. Paolo Tedesco Paolo Tedesco This is one of those cases where context is important - in CLR terms, the derived constructor is executed first. In C terms, the base constructor is executed first. There are a few oddities like this where the specs disagree; for instance, on whether structs have a parameterless constructor or not. Actually, it looks like I spoke too fast. Now I've consulted the spec, and while it says that the constructor-initializer is executed before the constructor-body, that counts as being included in the overall constructor.

So you're entirely right from both perspectives : — Jon Skeet. Mastermind Mastermind 3 3 bronze badges. The calling order is derived class field initializer base class field initializer base class constructor derived class constructor You can treat 2 and 3 as a whole to construct the base class.

The example using System; using System. Sqrt 2. Eric Lippert had an interesting post on the related issue of object initialization, which explains the reason for the ordering of constructors and field initializers: Why Do Initializers Run In The Opposite Order As Constructors? The Exception Constructor will be called, then your Child class constructor will be called. Member variables don't have the same concept of definite assignment as local variables.

They have a default value. What's interesting in C is that the variable initializers are run before the base constructor instead of after. Java has the latter behaviour. C supports overloading of constructors, that means we can have constructors with different set of parameters.

So our class can be like this:. Well, note here that call to the constructor now depends on the way you instantiate the object.

For example:. Another thing which we must know is the execution sequence i. Here if I instantiate the object as. So practically the definition of the method:. Now what will be the execution sequence here: If I create the object of the Derived class as. Note: If we do not provide initializer referring to the base class constructor then it executes the no parameter constructor of the base class.

Note one thing here: We are not making any explicit call to the constructor of base class neither by initializer nor by the base keyword, but it is still executing. This is the normal behavior of the constructor.

Here the new keyword base has come into picture. This refers to the base class of the current class. So, here it refers to the myBaseClass.



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